(c-1)(c^2-25)=0

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Solution for (c-1)(c^2-25)=0 equation: 


Simplifying
(c + -1)(c2 + -25) = 0

Reorder the terms:
(-1 + c)(c2 + -25) = 0

Reorder the terms:
(-1 + c)(-25 + c2) = 0

Multiply (-1 + c) * (-25 + c2)
(-1(-25 + c2) + c(-25 + c2)) = 0
((-25 * -1 + c2 * -1) + c(-25 + c2)) = 0
((25 + -1c2) + c(-25 + c2)) = 0
(25 + -1c2 + (-25 * c + c2 * c)) = 0
(25 + -1c2 + (-25c + c3)) = 0

Reorder the terms:
(25 + -25c + -1c2 + c3) = 0
(25 + -25c + -1c2 + c3) = 0

Solving
25 + -25c + -1c2 + c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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